스프링 데이터 JPA는 레포지토리가 인터페이스 이기 때문에 사용자 정의 repository를 만들어야 한다.
public interface MemberRepositoryCustom {
List<MemberTeamDto> search(MemberSearchCondition condition);
}
MemberRepositoryImpl
public class MemberRepositoryImpl implements MemberRepositoryCustom {
private final JPAQueryFactory queryFactory;
public MemberRepositoryImpl(EntityManager em) {
this.queryFactory = new JPAQueryFactory(em);
}
@Override
public List<MemberTeamDto> search(MemberSearchCondition condition) {
return queryFactory
.select(new QMemberTeamDto(
member.id.as("memberId"),
member.username,
member.age,
team.id.as("teamId"),
team.name.as("teamName")
))
.from(member)
.leftJoin(member.team, team)
.where(
usernameEq(condition.getUsername()),
teamNameEq(condition.getTeamName()),
ageBetween(condition.getAgeLoe(), condition.getAgeGoe())
)
.fetch();
}
private BooleanExpression ageBetween(Integer ageLoe, Integer ageGoe) {
return ageLoe != null && ageGoe != null ? ageLoe(ageLoe).and(ageGoe(ageGoe)) : null;
}
private BooleanExpression usernameEq(String username) {
return hasText(username) ? member.username.eq(username) : null;
}
private BooleanExpression teamNameEq(String teamName) {
return hasText(teamName) ? team.name.eq(teamName) : null;
}
private BooleanExpression ageGoe(Integer ageGoe) {
return ageGoe != null ? member.age.goe(ageGoe) : null;
}
private BooleanExpression ageLoe(Integer ageLoe) {
return ageLoe != null ? member.age.loe(ageLoe) : null;
}
}
MemberRepository
public interface MemberRepository extends JpaRepository<Member, Long>, MemberRepositoryCustom {
List<Member> findByUsername(String username);
}
테스트
@Test
public void searchTest() {
Team teamA = new Team("teamA");
Team teamB = new Team("teamB");
em.persist(teamA);
em.persist(teamB);
Member member1 = new Member("member1", 10, teamA);
Member member2 = new Member("member2", 20, teamA);
Member member3 = new Member("member3", 30, teamB);
Member member4 = new Member("member4", 40, teamB);
em.persist(member1);
em.persist(member2);
em.persist(member3);
em.persist(member4);
MemberSearchCondition condition = new MemberSearchCondition();
// condition.setAgeGoe(20);
// condition.setAgeLoe(40);
condition.setTeamName("teamB");
List<MemberTeamDto> result = memberRepository.search(condition);
assertThat(result).extracting("username").containsExactly("member3", "member4");
}
너무 조회가 복잡하다면 이런 고민을 해볼 필요가 있다.